[英]Convert list of string into comma separated 2D NumPy
I have a dataset like the following: 我有一个如下数据集:
0000000000000001,0
0000000000000010,0
0000000000000011,1
0000000000000100,1
0000000000000101,1
0000000000000110,0
0000000000000111,1
0000000000001000,0
0000000000001001,0
.
.
.
I want to convert the first column from each row to be a comma seperated something like this: 我想将每行的第一列转换为逗号分隔,如下所示:
From 0000000000000001,0
to 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0
从0000000000000001,0
到0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0
The following code has a small issue: full_data
is not 2D numpy of integers, yet it is 1D of string. 下面的代码有一个小问题: full_data
不是2D numpy整数,但它是1D的字符串。 I am not sure how to fix that. 我不知道如何解决这个问题。 Any hint is appreciated. 任何提示都表示赞赏。
data = []
my_data = np.genfromtxt('file.csv', delimiter=',', dtype='str')[:,0]
for i in my_data:
x= np.asarray(i)
data.append(x.tolist())
full_data = np.asarray(data)
Thank you 谢谢
This is one approach. 这是一种方法。
Demo: 演示:
import numpy as np
data = []
my_data = np.genfromtxt(filename, delimiter=',', dtype='str')
data = [list(i) + [j] for i, j in my_data]
print(data)
Output: 输出:
[
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '0'],
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '0', '0'],
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '1', '1'],
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '0', '0', '1'],
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '0', '1', '1'],
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '1', '0', '0'],
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '1', '1', '1'],
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '0', '0', '0', '0'],
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '0', '1', '0', '0', '1', '0']
]
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