如何显示div中字符串中的前两个单词并保留在其他span php中？

Question

I want to display string in different div and span, but can't able to do that. I am using below code to do that, but it not works. Can anyone help me solve out problem?

Want to display like this:

Input String: Lorem ispum dolor text si sample dummy text.

Output: Lorem ispum <span> dolor text si sample dummy text.</span>

if(!empty($extraData['heading_text']) && str_word_count($extraData['heading_text']) >= 3) :
  $getwords = explode(" ", $extraData['heading_text']);
  echo $getwords[0].' '.$getwords[1] .' '.'<span>'.$getwords[2]. '</span>';
  unset($getwords[0]);
  unset($getwords[1]);
  unset($getwords[2]);
  echo  implode(" ", array_values($getwords));
else :
  echo $extraData['heading_text']; 
endif;

Answer 1

Well, just extract and output the tokens you are interested in:

<?php  
$input = "Lorem ispum dolor text si sample dummy text.";
preg_match('/^(\w+\s+\w+)\s+(.*)$/', $input, $token);
echo sprintf("<div>%s</div>\n<span>%s</span>\n", $token[1], $token[2]);

The output obviously is:

<div>Lorem ispum</div>
<span>dolor text si sample dummy text.</span>

The same certainly is possible using explode() too, but much more complex:

<?php
$input = "Lorem ispum dolor text si sample dummy text.";
$word = explode(" ", $input);
echo sprintf("<div>%s %s</div>\n", $word[0], $word[1]);
unset($word[0]); 
unset($word[1]);
echo sprintf("<span>%s</span>\n", implode(" ", $word));

---

UPDATE:

The first alternative, based on a regular expression, only works for true "words", that is defined pretty strict. You can somewhat "weaker" that strict behavior by slightly altering the expression:

<?php  
$input = "What we've Done";
preg_match('/^([^\s]+\s+[^\s]+)\s+(.*)$/', $input, $token);
echo sprintf("<div>%s</div>\n<span>%s</span>\n", $token[1], $token[2]);

With that modification the output again is as expected:

<div>What we've</div>
<span>Done</span>