如果不为null，则将参数传递给方法

Question

How do i include argument in python only if its not null? Following code works fine if i pass valid color to method doSomething. Now color is sometimes null (like null in java, i guess its None or nil in python), whic is when printColor throws exception. How can i avoid this?

Invalid type for parameter packageNamespace, value: None

response = client.printColor(
            color = color # Only include this param is not None/Null
   )

response = client.printColor() # this works

Answer 1

You can filter None s out of a dict:

kwargs = {
    'color': color,
    ⋮
}

response = client.printColor(**{k: v for k, v in kwargs.items() if v is not None})

Or do the same thing as a function:

def none_to_default(**kwargs):
    return {k: v for k, v in kwargs.items() if v is not None}


client.printColor(**none_to_default(
    color=color,
    ⋮
))

This might not be the best solution to the problem, though. It would be ideal if you could show the real function['s documentation].