C2678二进制'=='：找不到使用'Card'类型的左操作数的运算符（或者没有可接受的转换）

Question

I am getting the above error caused by the tie break function

#include <vector>
#include <iostream>
#include <algorithm>

class Hand{
private:
std::vector<Card> cards;
public:
  PokerHand(Card c1, Card c2) {
      cards.push_back(c1);
      cards.push_back(c2);
      cards.push_back(c3);
      cards.push_back(c4);
      cards.push_back(c5);
  }
bool breakTie(const PokerHand& other) const{
    std::vector<Card> temp1 = { cards };
    std::vector<Card> temp2 = { other.getCards()};
    return std::find(temp1.begin(), temp1.end(), 2) <    std::find(temp2.begin(), temp2.end(), 2)
}
std::vector<Card> getCards(){
    return cards;
}
};

class Card{
private:
    int value;
public:
    bool operator ==(const Card& right)const {
        return (this->value == right.getValue());
    }
    int getValue(){
        return value;
    }
    Card(int value){
        this->value=value;
    }
};

int main(){
    Card a(4);
    Card b(5);
    Hand hand(a,b);
    hand.breakTie();
    return 0;
}

From what i understand the error means that i am trying to change a const variable. What I don't understand is how I am changing a const variable?

Help greatly appreciated.

Answer 1

You are calling find on a vector of Card s with the integer 2 . You are getting that error because 2 is not a Card , nor is there any constructor for Card that takes one integer parameter that can be used (either there is none, or the one that exists is marked explicit ).

You need to clarify (to the compiler) what it is your looking for. What is Card 2?