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SQL Distinct计数累积

[英]SQL Distinct count cumulative

I want to do a query that maps the following input to the following output: 我想做一个查询,将以下输入映射到以下输出:

Input: 输入:

a,b,id    
x,y,1    
x,y,2    
x,z,3    
t,z,4    
t,y,5
t,y,6

Output: 输出:

count,id    
1,1    
1,2    
2,3    
1,4    
2,5
2,6

Using the following logic: 使用以下逻辑:

For every different group in a, count how many different b elements are for ids lower or equal than the current id. 对于a中的每个不同组,计算有多少不同的b元素用于id低于或等于当前id。


I have tried: 我努力了:

SELECT COUNT(a), b, id FROM table GROUP BY b

but this doesn't give any cumulative results. 但这并没有给出任何累积结果。

One method is a correlated subquery: 一种方法是相关子查询:

select t.*,
       (select count(distinct t2.b) from t t2 where t2.a = t.a and t2.id <= t.id) 
from t;

For performance, you want in index on t(a, b) . 对于性能,您需要在t(a, b)上的索引。

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