使用开始月份和结束月份的时刻获取一系列月份

Question

I am using a moment library and I would like to use it for getting an array of string months, with the starting date and the end date. So, for example when I have two dates:

const from = moment('2018-05-01', 'YYYY-MM-DD').format('MMMM');
  const to = moment('2018-07-01', 'YYYY-MM-DD').format('MMMM');

How can I then get the range of months as a string array, that would then look like this for the given dates:

['May', 'June', 'July']

Is there a way we can achieve this with moment, and what would be the most elegant way to do this?

Answer 1

Kindly, find the below format for moment.

var fromDate = moment('2018-05-01','YYYY-MM-DD');
var toDate = moment('2018-07-01','YYYY-MM-DD');
var monthData = [];

while (toDate > fromDate || fromDate.format('M') === toDate.format('M')){

monthData.push(fromDate.format('MMMM'));
fromDate.add(1,'month');

}
console.log(monthData); // Output ["May", "June", "July"]

Thanks

Answer 2

You can use moment.months and slice it to get only needed months

 var months = moment.months(); console.log(JSON.stringify(months)) console.log(JSON.stringify(months.slice(4,7)))

 <script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>

Answer 3

Just to show a solution without moment.js.

Month names are available in the browser default language using toLocaleString . To get the names for months from the 3rd to 5th months inclusive, slice them from the array, eg

 /* Return array of month names for month number range in the * browser default language. * Eg 3,5 returns ['March','April','May] with default language English * Assumes Gregorian calendar, 12 months in year. If input is invalid, * returns an empty array * * @param {number|string} [startMonth=1] - calendar month number * @param {number|string} [endMonth=12] - calendar month number * @returns {string[]} Array of month names from startMonth to endMonth inclusive. */ var getMonthNames = (function () { var months = new Array(12).fill(0).map((v,i)=> new Date(2000,i).toLocaleString(undefined,{month:'long'}) ); return function(startMonth=1, endMonth=12) { return isNaN(+startMonth) || isNaN(+endMonth)? []: months.slice(--startMonth, endMonth); } }()); // Example [['03', '03'], // Single month ['06'], // Month to end of year [], // Month 1 to 12 ['01', '09'], // Month 1 to month 9 ['foo'] // Erroneous input ].forEach(args => console.log(`${args.toString()}: ${getMonthNames(...args).join(', ')}`) );

Creating the month name list is a little expensive, but it only runs once and it only needs 12 Dates so trivial.

It needs better error handling, eg check start <= end , 0 < start < 13 , 0 < end < 13 , start and end are integers, etc.

Answer 4

If you are trying to get the month range in this format "2022-12-11T00:00:00+01:00 2022-12-17T23:59:59+01:00"

This would do the trick

const start = moment().subtract(1, 'week').startOf('week').format();
const end = moment().subtract(1, 'week').endOf('week').format();

I hope this was helpful