调用函数进行打印时，如何从我的void函数中获取用户输入？

Question

I have a code that will turn a word into pig latin, I'm getting user input from a function. What do i need to put into the

print(convert_word(n))

to make it print with user input?

def void(n):
n = input("Enter the word you want converted to Pig Latin: ")
return n


VOWELS = ('a', 'e', 'i', 'o', 'u')

# Function definition

def convert_word(word):


# Assign the first letter of word to variable first_letter
first_letter = word[0]

# Check if the word starts with a vowel
if first_letter in VOWELS:

    # If it is a vowel, then keep the word as it is and add "hay" to the end
    return word + "hay"

# If the word does not start with a vowel
else:
        # Returns the word except word[0] and add "ay" at the end of the string
    return word[1:] + word[0] + "ay"


# Prompt the user to enter the input string


# Call the function to convert the word to pigLatin
print(convert_word(n))

Answer 1

Since void() only calls input() , you could do away with that function entirely and just call convert_word() like this:

print(convert_word(input('some prompt >')))

If you really do need the void() function for some reason:

print(convert_word(void()))

If you like, you can change the declaration of void() to remove the input argument, as it is never used.