创造所有可能性的功能

Question

var parameter1 = "String";

var parameter 2 = "-";

function test(parameter1, parameter2) 

var parameter1 = "String";

var parameter 2 = "-";

function test(parameter1, parameter2)

result:

String

S-tring

St-ring

Str-ing

Stri-ng

String

Str-in-g

St-ri-ng

St-ri-ng

St-rin-g

S-tr-ing

S-tr-i-ng

S-tr-ing

S-tr-in-g

S-tri-ng

S-tri-ng

S-trin-g

St-ring

St-r-ing

St-ri-ng

St-ring

St-r-in-g

St-ri-ng

St-ri-ng

St-rin-g

Str-ing

Str-i-ng

Str-ing

Str-in-g

Stri-ng

Stri-ng

Strin-g

**So far tried to achieve this result but nothing is worked any help to get this result is appreciated. Thank you ** i tried this way but i want to get exact output as above result

     var array1=["S","T","R","I","N","G"];
      var array2=["-"];
     combos = [] //or combos = new Array(2);

     for(var i = 0; i < array1.length; i++)
    {
     for(var j = 0; j < array2.length; j++)
     {


        combos.push(array1[i] + array2[j])
     }
  console.log(combos);
}

Answer 1

You could take a generator for getting parts of a string and iterate this values by checking if the right side has some character to split. If that is the case call the function again with that string and map new pairs for the result set.

 function* split(string) { var i = 0; while (++i < string.length) { yield [string.slice(0, i), string.slice(i)]; } } function fn(string, delimiter) { const join = l => r => [l, r].join(delimiter); var result = [string], parts; for (var [left, right] of split(string)) { parts = join(left); if (right.length > 1) { result.push(...fn(right, delimiter).map(parts)); } else { result.push(parts(right)); } } return result; } console.log(fn('String', '-')); 

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