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将年数转换为dateName?

[英]Convert number of years into dateName?

So I'm calculating the datediff in years and getting a numerical value (Ex: 16.166666) What would be the best solution to turn that value into Date Names. 因此,我计算年份中的约会数并得到一个数值(例如:16.166666)将该值转换为日期名称的最佳解决方案是什么。

For example 16.166 years would turn into: 16 years and 1 month? 例如16。1666年会变成:16年1个月?

Example

Declare @Value float= 16.166

Select Years   = floor(@Value)
      ,Months  = floor((@Value - floor(@Value)) * 12)
      ,OrAsStr = ltrim(
                 replace(
                 replace(
                 concat(' ',floor(@Value),' Years ',floor((@Value - floor(@Value)) * 12),' Months')
                 ,' 1 Years ',' 1 Year ')
                 ,' 1 Months',' 1 Month')
                 )

Returns 返回

Years   Months  OrAsStr
16      1       16 Years 1 Month

According to your comment 根据你的评论

I have two date columns which I need to find the date difference , then convert to a string: Ex: 16 years and 1 month. 我有两个日期列,我需要找到日期差异,然后转换为字符串:例如:16年零1个月。

You can do like 你可以这样做

DECLARE
       @Start DATE = '2000-01-01',
       @End   DATE = '2016-02-01';

SELECT CAST(T.Years AS VARCHAR(10)) + ' Years and ' + 
       CAST(DATEDIFF(Month, @Start, DATEADD(Year, - T.Years, @End)) AS VARCHAR(2)) + ' Months.'
FROM
    (
        SELECT DATEDIFF(Year, @Start, @End) Years
    ) T;

OR 要么

SELECT CAST(DATEDIFF(Year, @Start, @End) AS VARCHAR(10)) + 
       ' Years and ' + 
       CAST(
             DATEDIFF(
                      Month, 
                      @Start, 
                      DATEADD(Year, - DATEDIFF(Year, @Start, @End), 
                      @End
                     )
           ) AS VARCHAR(2)) + ' Months.';

Returns 返回

+------------------------+
| 16 Years and 1 Months. |
+------------------------+

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