[英]counting confusion_matrix in python
I wan to calculate calculate True_Positive, False_Positive,False_Negative, True_Negative
for three categories. 我想计算三个类别的
True_Positive, False_Positive,False_Negative, True_Negative
。 I used to have two classes Cat
Dog
and this is the way i used to calculate my confusion_matrix 我以前有两个班级的
Cat
Dog
,这是我用来计算confusion_matrix的方式
Y_pred has either a cat or dog
y_true has either a cat or dog
confusion_matrix_output =confusion_matrix(y_true, y_pred)
True_Positive = confusion_matrix_output[0][0]
False_Positive = confusion_matrix_output[0][1]
False_Negative = confusion_matrix_output[1][0]
True_Negative = confusion_matrix_output[1][1]
Now i have three classes 'Cat' 'Dog' 'rabbit' 现在我有三个班级'猫''狗''兔子'
Y_pred has Cat Dog rabbit
y_true has Cat Dog rabbit
How to calculate True_Positive, False_Positive,False_Negative, True_Negative ??? 如何计算True_Positive,False_Positive,False_Negative,True_Negative ???
Now you have three classes, so it's not just positives and negatives anymore. 现在您有了三个类别,因此不再只是正面和负面。 You have to look at: Cat predicted as a cat, Dog predicted as Dog, Rabbit predicted as Rabbit, Dog predicted as cat, Cat predicted as Dog, and so on.
您必须查看:将Cat预测为猫,将Dog预测为Dog,将Rabbit预测为Rabbit,将Dog预测为cat,将Cat预测为Dog,等等。 You'll have 3 by 3 confusion matrix for this situation.
对于这种情况,您将有3 x 3的混淆矩阵。 Confusion matrix size is n by n, where n is the number of classes
混淆矩阵的大小为n x n,其中n为类别数
sklearn.metrics.confusion_matrix
abstracts away all that and creates an n by n matrix for you. sklearn.metrics.confusion_matrix
将所有sklearn.metrics.confusion_matrix
抽象化,并为您创建一个n by n矩阵。 Try this: 尝试这个:
from sklearn.metrics import confusion_matrix
confusion_matrix_output =confusion_matrix(y_true, y_pred)
Cat_P_Cat = confusion_matrix_output[0][0]
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