Spring Data JPA findAll与介于两者之间的表（PropertyReferenceException）

Question

Here is my model:

• one AdmisHistory is linked to many Admis

• one Admis is linked to 0 or one AdmisRejet

Entities:

public class AdmisHistory {
    @OneToMany(fetch = FetchType.EAGER, mappedBy = "admisHistory", cascade = CascadeType.ALL, orphanRemoval = true)
    private List<Admis> admis = new ArrayList<>();

public class Admis {
    @ManyToOne(cascade = CascadeType.ALL)
    @JoinColumn(name = ADMIS_HISTORY_ID)
    private AdmisHistory admisHistory;

    @OneToOne(mappedBy = "admis", cascade = CascadeType.ALL)
    private AdmisRejet admisRejet;

public class AdmisRejet {
    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(name = ADMIS_ID)
    private Admis admis;

Given an AdmisHistory, I want to retrieve the list of AdmisRejet.

I manage to do it like this:

public interface AdmisRepository extends CrudRepository<Admis, Long> {
    List<Admis> findAllAdmisByAdmisHistory(AdmisHistory admisHistory);
...

// It work llike this:
 admisRepository.findAllAdmisByAdmisHistory(admisHistory)
.stream()
.filter(adm -> adm.getAdmisRejet() != null)

Now I would like to do it in a simple call on a repository. It would be much more efficient and readable.

Something like this:

 public interface AdmisRejetRepository extends CrudRepository<AdmisRejet, Long> {
        List< AdmisRejet> findAllAdmisRejetByAdmisHistory(AdmisHistory admisHistory);
    }

But I get this error:

Caused by: org.springframework.data.mapping.PropertyReferenceException: No property history found for type Admis! Traversed path: AdmisRejet.admis.'

I try with @Query but the syntax is not good:

public interface AdmisRejetRepository extends CrudRepository<AdmisRejet, Long> {
    @Query("SELECT a " +
            "FROM AdmisRejet ar " +
            "LEFT JOIN ar.admis a, " +
            "LEFT JOIN a.admisHistory ah " +
            "WHERE ah = :admisHistory")
    List< AdmisRejet> findAllByHistory(AdmisHistory admisHistory);
}

How can I do it ?

Answer 1

If I'm reading the spec correct this should work.

@Query("SELECT DISTINCT ar 
        FROM AdmisRejet ar
        WHERE ar.admis.admisHistory = :history")
List<AdmisRejet> findAdmisRejetByAdmisHistory(AdmisHistory history);

Answer 2

try

  List< AdmisRejet> findAllAdmisRejetByAdmisHistoryWhereAdmisRejecIsNotNul(AdmisHistory admisHistory);

or something similar.