SQL查询找到具有最大总和的行

Question

I have following 'Scores' table which has score of players in a specific year

        Sid    Name     Score     Year
         1     John     500      2016
         2     Kim      900      2015
         3     Ren      300      2016
         4     John     600      2015
         5     Kim      200      2016     
         6     Ren      200      2016

Find the player who has scored maximum runs in 2016

I can find this using the below query

Select   Name 
  from
     ( select Name
            , sum(Score) as sumScore 
         from Scores 
       where year=2016 
       group
         by Name
     ) sub 
  order 
    by sumScore desc 
 limit 1;

Ren

How can i find the same without using order by?

I tried below but it doesn't work as it can't refer sub in 2nd where clause and complains relation sub doesn't exist

select Name from(select Name,sum(Score) as sumScore from Scores 
where year=2016 group by Name)sub where sumScore=(select max(sumScore) from sub)

Answer 1

One simple method uses window functions:

select s.*
from (select s.*, max(s.score) over (partition by year) as max_score
      from scores s
      where year = 2016
     ) s
where score = max_score;

Answer 2

You can try using correlated subquery

DEMO

select * from tablename a where score in 
(select max(score) from tablename b where a.year=b.year and b.year=2016)
and a.year=2016

OR you can use window function row_number() like below

select * from 
(
select *,row_number() over(partition by yr order by score desc) as rn from cte1 
)a where rn=1 and yr=2016

OUTPUT:

id  name    score   yr
1   John    500    2016

Answer 3

SELECT Scores.Name, SUM(Scores.Score)
FROM (
      select Name,sum(Score) as sumScore, Years 
      from Scores 
      where Years=2016 
      group by Name, Years
     )sub INNER JOIN Scores ON sub.Name = Scores.Name
GROUP BY Scores.Name
HAVING SUM(Scores.Score) = MAX(sub.sumScore)

Answer 4

You could also use common table expression in combination with dense rank

with cte as (
    select *, 
    DENSE_RANK() OVER(ORDER BY score desc, year) rank 
    from demo 
    where year = 2016
)
select * 
from cte 
where rank = 1

Demo

Edit to get players with max score of 2016 you can tweak above query as

with cte as (
    select name,year ,
    DENSE_RANK() OVER(ORDER BY sum(score) desc, year) rank 
    from demo 
    where year = 2016
    group by name,year
)
select * 
from cte 
where rank = 1

Demo