[英]Passing php variable into javascript parameter
I want to pass a php variable into a jquery function parameter, when i added an id to each loop it only return the first one. 我想将php变量传递给jquery函数参数,当我向每个循环添加一个id时,它仅返回第一个。 How to do it right ?
怎么做对?
php code : PHP代码:
foreach ($record as $key): ?>
<tr>
<td><a href="" onclick="update_amarta(<?php echo $key->SiteID ?>)"> NOT YET</a></td>
</tr>
<?php endforeach; ?>
Javascript : Javascript:
<script type="text/javascript">
function update_amarta(id) {
alert(id);
};
</script>
Hi @highcal please use this PHP code inside inverted comma's. 嗨@highcal,请在反逗号内使用此PHP代码。 something like that
这样的东西
<a href="" onclick="update_amarta('<?php echo $key->SiteID ?>')"> NOT YET</a>
Hope this will work for you. 希望这对您有用。 Thank You.
谢谢。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.