Groovy-如何拆分包含多个FileName但其中一些包含空格的String？

Question

How to split a string containing a number of file names (including names containing spaces)?

Example String:

randomFolderNameA/path/to/file1.java randomFolderNameB/path/to/file2.sql randomFolderNameC/path/to/file3 with space.xml file4 with space.sql 

Expected output:

randomFolderNameA/path/to/file1.java
randomFolderNameB/path/to/file2.sql
randomFolderNameC/path/to/file3 with space.xml
file4 with space.sql 

Answer 1

Assuming all your paths are absolute, you can use look-ahead assertion in your regex:

def text = "/path/to/file1.java /path/to/file2.sql /path/to/file3 with space.xml"
println text.split(" (?=/)")

And that outputs [/path/to/file1.java, /path/to/file2.sql, /path/to/file3 with space.xml]

Taht regex splits the string on a space followed by a /

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EDIT: For the updated example, it's possible to look at extensions in file names, although you'd need to carefully consider what your input can include:

def text = "randomFolderNameA/path/to/file1.java randomFolderNameB/path/to/file2.sql randomFolderNameC/path/to/file3 with space.xml file4 with space.sql"

println text.split("(?<=\\.[a-zA-Z0-9]{1,4}) ")

That outputs the following, as expected:

[randomFolderNameA/path/to/file1.java, 
 randomFolderNameB/path/to/file2.sql, 
 randomFolderNameC/path/to/file3 with space.xml, 
 file4 with space.sql]

But as noted above, you need to be sure that paths only include file names and the extension regex is valid (I used "a dot followed by 1 to 4 alpha-numeric characters")