使用嵌套列表检查python列表

Question

I have two python lists. For example:

a = ['1', '2', '3', '4']
b =['1,2', '3,4', '3,33,34', '44']

I need to compare whether list[0] which is one is in b[0] which is 1, 2 and it has to return the output as 1 if it is present and 0 if it is not present.

The final output should be like:

1 (as 1 is present in 1,2)    
0 (as 2 is not present in 3,4)    
1 (as 3 is present in 3,33,34)    
0 (as 4 is not present in 44)

Please do help me in writing a code for this in python as I'm a beginner in this.

Answer 1

Use zip

Ex:

a = ['1','2','3','4']
b =['1,2', '3,4', '3,33,34', '44']

for i, v in zip(a, b):
    if i in v.split(","):     #Check if element in b 
        print(1)
    else:
        print(0)

Output:

1
0
1
0

Answer 2

You can also try the following:

for index, value in enumerate(a):  
    if value in b[index].split(","):  
        print(1)  
    else:  
        print(0)