[英]Read whole stdin to buffer
i have an input with newlines and i need to read it to buffer. 我有换行符输入,我需要读取它以缓冲。 Format is restricted to the structure.
格式仅限于结构。
Input looks like this: 输入看起来像这样:
{
[
5.5
;
1
]
, [ 1; 2 ] ,[3; 4]}
And the code I have is like this: 我的代码是这样的:
char *s2 = NULL;
size_t n = 0;
int slozZav = 0;
int hranZav = 0;
getline(&s2, &n, stdin);
if(sscanf(s2, " %c [ %lf ; %lf ] , [ %lf ; %lf ] , [ %lf ; %lf ] %c", &s1, &Ax, &Ay, &Bx, &By, &Cx, &Cy, &s) == 8 && s=='}' && s1=='{' && slozZav % 2 == 0 && hranZav % 2 == 0) { ... }
Am I doing it the right way with getline? 我用getline正确的方法吗? I tried to read it with
scanf()
, but then I can't copy stdin to buffer. 我试图用
scanf()
读取它,但是后来我无法将stdin复制到缓冲区。
getline
reads until it encounters a new line; getline
读取直到遇到新行; hence, it will stop when you press enter the first time. 因此,它将在您第一次按Enter时停止。
To read in the complete structure to be scanned, try: 要读取要扫描的完整结构,请尝试:
getdelim(&s2, &n, '}', stdin);
This way, new lines will be read in as well, and reading will stop after having read the delimiter }
. 这样,也将读入新行,并且在读取定界符
}
之后将停止读取。
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