[英]Search JSON data in tableView swift4
I am trying to show jsondata
in to the tableView
and search country
from the searchBar
but getting error
in to the textDidChange
function.我正在尝试将
jsondata
显示到tableView
并从searchBar
搜索country
,但在textDidChange
函数中error
。
I want the user to enter three words into the searchBar
then tableView
will open and search data.我想用户输入三个字到
searchBar
,然后tableView
将打开和搜索数据。
struct country : Decodable {
let name : String
let capital : String
let region : String
}
class ViewController: UIViewController,UISearchBarDelegate {
var isSearch : Bool = false
var countries = [country]()
var arrFilter:[String] = []
@IBOutlet weak var tableview: UITableView!
@IBOutlet weak var searchbar: UISearchBar!
override func viewDidLoad() {
super.viewDidLoad()
tableview.dataSource = self
tableview.delegate = self
searchbar.delegate = self
let jsonurl = "https://restcountries.eu/rest/v2/all"
let url = URL(string: jsonurl)
URLSession.shared.dataTask(with: url!) { (data, response, error) in
do{
self.countries = try JSONDecoder().decode([country].self, from: data!)
}
catch{
print("Error")
}
DispatchQueue.main.async {
self.tableview.reloadData()
}
}.resume()
}
shows error into this part.在这部分显示错误。
func searchBar(searchBar: UISearchBar, textDidChange searchText: String) {
if searchText.characters.count == 0 {
isSearch = false;
self.tableview.reloadData()
} else {
arrFilter = countries.filter({ (text) -> Bool in
let tmp: NSString = text
let range = tmp.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch)
return range.location != NSNotFound
})
if(arrFilter.count == 0){
isSearch = false;
} else {
isSearch = true;
}
self.tableview.reloadData()
}
}
}
my table view part我的表视图部分
extension ViewController : UITableViewDelegate, UITableViewDataSource{
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
if(isSearch){
return arrFilter.count
}
else{
return countries.coun
}
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableview.dequeueReusableCell(withIdentifier: "cell", for: indexPath)
if(isSearch){
cell.textLabel?.text = arrFilter[indexPath.row]
}else{
cell.textLabel?.text = countries[indexPath.row].name.capitalized
}
return cell
}
}
NSString
in Swift and the Foundation
rangeOfString
API, use native String
and native range(of
.Foundation
rangeOfString
API 中使用NSString
,使用原生String
和原生range(of
..count == 0
..count == 0
的空数组。 There is isEmpty
.isEmpty
。struct Country ...
. struct Country ...
. The error occurs because you are filtering Country
instances and actually you are looking for its name
or its region
.发生错误是因为您正在过滤
Country
实例,而实际上您正在寻找它的name
或它的region
。
This is a pure Swift version of your code这是您代码的纯 Swift 版本
func searchBar(searchBar: UISearchBar, textDidChange searchText: String) {
if searchText.isEmpty {
isSearch = false
} else {
arrFilter = countries.filter( $0.name.range(of: searchText, options: .caseInsensitive) != nil }
isSearch = !arrFilter.isEmpty
}
self.tableview.reloadData()
}
If you want to filter for name
and region
write如果要过滤
name
和region
写入
arrFilter = countries.filter( $0.name.range(of: searchText, options: .caseInsensitive) != nil
|| $0.region.range(of: searchText, options: .caseInsensitive) != nil }
With this syntax declare arrFilter
使用此语法声明
arrFilter
var arrFilter = [Country]()
and in cellForRow
write并在
cellForRow
写入
let dataArray = isSearch ? arrFilter : countries
cell.textLabel?.text = dataArray[indexPath.row].name.capitalized
You are getting country object of your array as a string so such an error occured.. Please do as below您正在以字符串形式获取数组的国家/地区对象,因此发生了这样的错误。请按以下步骤操作
var arrFilter:[country] = [country]()
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableview.dequeueReusableCell(withIdentifier: "cell", for: indexPath)
if(isSearch){
cell.textLabel?.text = arrFilter[indexPath.row].name.capitalized
}else{
cell.textLabel?.text = countries[indexPath.row].name.capitalized
}
return cell
}
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
if searchText.characters.count == 0 {
isSearch = false;
self.tableview.reloadData()
} else {
arrFilter = countries.filter({ (country) -> Bool in
let tmp: NSString = NSString.init(string: country.name)
let range = tmp.range(of: searchText, options: NSString.CompareOptions.caseInsensitive)
return range.location != NSNotFound
})
if(arrFilter.count == 0){
isSearch = false;
} else {
isSearch = true;
}
self.tableview.reloadData()
}
}
First you can not assign a value type [Country] to [String].For example when assign a arrFilter at that time country.filter always return country type value not a string type.首先,您不能将值类型 [Country] 分配给 [String]。例如,当分配 arrFilter 时 country.filter 始终返回国家类型值而不是字符串类型。
use below code to helping you,使用下面的代码来帮助你,
var countries = [country]()
var arrFilter:[country] = [country]()
inside the viewdidLoad在 viewdidLoad 里面
override func viewDidLoad() {
self.countries.append(country(name: "India", capital: "New Delhi", region: "Asia"))
self.countries.append(country(name: "Indonesia", capital: "Jakarta", region: "region"))
self.countries.append(country(name: "Australia", capital: "Canberra", region: "Austrialia"))
// Do any additional setup after loading the view.
}
And和
self.arrFilter = self.countries.filter({ (country) -> Bool in
let temp : NSString = country.name as NSString //or you can use country.capital or country.region
let range = temp.range(of: "ind", options: .caseInsensitive)
print(range.location)
print(range.length)
print(temp)
return range.location != NSNotFound
})
Thanks谢谢
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.