如何只用一个空格替换字符串字符？

Question

I'm trying to replace all "WUB" in a string with a blank space. The problem is, if I have 2 "WUB" in a row, it will return 2 blank spaces. How do only return 1 blank space if I have "WUBWUB"?

function songDecoder(song) {
    var replacedLyrics = song.replace(/#|WUB/g,' ');
    return replacedLyrics;
}

Answer 1

Try this regex /(WUB)+/g it will match 1 or more element in the parenthesis

 function songDecoder(song) { var replacedLyrics = song.replace(/(WUB)+/g,' '); return (replacedLyrics); } console.log(songDecoder("hello world !")); console.log(songDecoder("WUB")); console.log(songDecoder("helloWUBWUBworldWUB!")); 

Answer 2

/#|WUB/g should be /#|(WUB)+/g for your purpose. Do you also want to replace multiple "#"s with a single space. Then you might want /(#|WUB)+/g

The parentheses group the target strings together, then plus seeks one or more repetition of the group.

If you don't want a space at the beginning or end of your string, that could be another regex function, but probably the most straightforward method is to use the .trim() function. So:

 alert( songDecoder('WUBYOUREWUBWELCOMEWUB') ) function songDecoder(song) { var replacedLyrics = song.replace(/(#|WUB)+/g,' ').trim(); return replacedLyrics; } 

Answer 3

Change your code to .replace(/#|(WUB)+/g, " "); .

This searches for as many "WUB's" in a row before replacing them with a blank space