如何使程序完成时绘制所有矩形，而不是一次绘制一次？

Question

My CS professor gave us an assignment to make a program that uses two lists to collect data on rectangles, and then to draw them into a window. I was able to make the program work by drawing the rectangles one at a time, but he said that I needed to make them all be drawn after the data was collected. I tried to do this with the variable "Bolorc", but all I was left with was a single rectangle at the end. What am I doing wrong?

from graphics import *

def main():

print('Enter data and I will draw you a rectangle.')

win = GraphWin('Rectangle Painter v1.0', 500, 500)


# The "Big Ole' List of Rectangle Coordinates"
Bolorc = []

# Asking for data to draw Rectangles
numRect = int(input('How many rectangles would you like to create? '))
for i in range(numRect):
    rec = input('Enter your information for Rectangle #' + str(i + 1) + ' (Ex: red x1 x2 y1 y2): ')
    rec1 = rec.split(sep = ' ')
    Bolorc = rec1 + Bolorc

# Drawing Rectangles
for i in range(numRect):
    Rec = Rectangle(Point(Bolorc[1],Bolorc[2]), Point(Bolorc[3], Bolorc[4]))
    Rec.setFill(Bolorc[0])
    Rec.setOutline('black')
    Rec.setWidth('2')
    Rec.draw(win)


main()

Answer 1

You are looping all the rectangles and are drawing only the first one.

Rec = Rectangle(Point(Bolorc[1],Bolorc[2]), Point(Bolorc[3], Bolorc[4]))
Rec.setFill(Bolorc[0])

draws only the first rectangle.

You have to change it so that the rectangle drawn differs according to i .

Inside your for loop,

offset = i * 5 # each rectangle is made up with 5 values
Rec = Rectangle(
    Point(Bolorc[offset + 1], Bolorc[offset + 2]),
     Point(Bolorc[offset + 3], Bolorc[offset + 4]))
Rec.setFill(Bolorc[offset])