如何为列表中的每个人分配一个数字？

Question

I'm struggling to think of a function that allows me to assign a number to each person in terms of their hierarchy eg person 1 with rank of 1 has a higher no. than other players

 People = ["Tz", "Bs", "Ds", "Kk", "Os", "Vs", "Dn"]

Answer 1

You can use dictionary instead of list . I would suggest you use from collections import defaultdict . By this way, you can even assign a tuple to one key. Even more, if you just passed the same key multiple times with different values it will store them under the same key.

>>> s = [('yellow', 1), ('blue', 2), ('yellow', 3), ('blue', 4), ('red', 1)]
>>> d = defaultdict(list)
>>> for k, v in s:
...     d[k].append(v)
...
>>> sorted(d.items())
[('blue', [2, 4]), ('red', [1]), ('yellow', [1, 3])]

Answer 2

You need a dictionary for this. Players = { "Rz": 1, "As" : 2 } It would be in the format {"player_name": strength}

Answer 3

You can solve it via using a dictionary, but there's also a design pattern where you'd use a second list.

players = ["Rz", "As", "Ts", "Dk", "Ms", "Ss", "Pn"]
strength = [5, 4, 3, 2, 1, 0, 0]

This would mean you can access the first players strength by its index in the players list.

players[0]
strenght[0]

This, of course, needs you to keep the players in the same order.