[英]sunday to saturday week date array in php
for getting sunday to saturday dates for calender week i am using that code in php : 为了获得日历周的周日至周六日期,我在php中使用了该代码:
$dt = strtotime(date('Y-m-d'));
$res['start'] = date('N', $dt)==1 ? date('Y-m-d', $dt) : date('Y-m-d', strtotime('last sunday', $dt));
$res['end'] = date('N', $dt)==7 ? date('Y-m-d', $dt) : date('Y-m-d', strtotime('saturday', $dt));
$day_of_week = date('N', strtotime($res['start']));
$given_date = strtotime( $res['end'] );
$first_of_week = date('Y-m-d', strtotime("- {$day_of_week} day", $given_date));
$first_of_week = strtotime($first_of_week);
for($i=1 ;$i<=7; $i++)
{
$datess[] = date('Y-m-d', strtotime("+ {$i} day", $first_of_week));
$week_array[] = date('m/d', strtotime("+ {$i} day", $first_of_week));
print_r($datess);
}
exit;
after this i am getting array from 2018-10-29 to 2018-11-04 but i want array from 2018-11-04 2018-11-10 what i am doing wrong here in this code can anyone please let me know or correct me where i am doing wrong in this code 在此之后,我将从2018-10-29到2018-11-04获取数组,但我想要从2018-11-04 2018-11-10数组,我在此代码中做错了什么,有人可以让我知道或纠正我在这段代码中我做错了的地方
Are you assuming Sunday is day of the week number 1
? 你假定星期日是一周数天
1
? And Saturday 7
? 还有星期六
7
?
If so, Sunday is 7
and Saturday 6
. 如果是这样,则星期日为
7
,星期六为6
。 So your code would look like this: 因此,您的代码如下所示:
$dt = strtotime(date('Y-m-d'));
$res['start'] = date('N', $dt) == 7 ? date('Y-m-d', $dt) : date('Y-m-d', strtotime('last sunday', $dt));
$res['end'] = date('N', $dt) == 6 ? date('Y-m-d', $dt) : date('Y-m-d', strtotime('saturday', $dt));
$day_of_week = date('N', strtotime($res['start']));
$given_date = strtotime($res['end']);
$first_of_week = date('Y-m-d', strtotime("- {$day_of_week} day", $given_date));
$first_of_week = strtotime($first_of_week);
for ($i = 1 ; $i <= 7; $i++) {
$datess[] = date('Y-m-d', strtotime("+ {$i} day", $first_of_week));
$week_array[] = date('m/d', strtotime("+ {$i} day", $first_of_week));
print_r($datess);
}
One solution using PHP powerful date functions time date and strtotime 一种使用PHP功能强大的日期函数time date和strtotime的解决方案
<?php
if (date('D') == 'Sun') {
$lsTimestamp = time();
} else {
$lsTimestamp = strtotime('last Sunday');
}
$dates = [date('Y-m-d', $lsTimestamp)];
for ($i = 1; $i <= 6; $i++) {
$dates[] = date('Y-m-d', strtotime('+' . $i . ' day', $lsTimestamp));
}
var_dump($dates);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.