如何从bash中的变量的curl响应中获取字符串？

Question

The bash script sends a curl The curl response example is

    {"code":"2aaea70fdccd7ad11e4ee8e82ec26162","nonce":1541355854942}

I need to get the random code "2aaea70fdccd7ad11e4ee8e82ec26162" (without quotes) and use it in the bash script.

Answer 1

Use jq to extract the value from the JSON, and command substitution to capture the output of the command:

code=$(curl ... | jq -r '.code')

The -r ( --raw ) prints the string directly instead of quoting it as in a JSON.

Answer 2

You can also achieve it by sed command if you don't want to install jq:

json=`curl ...`
code=$(echo "$json" | sed -nE 's/.*"code":"([^\"]*)",".*/\1/p')