如何在C中获取内存地址的值

Question

I am trying to access the value of a memory access, but I keep getting the address, when I print the output.

char c[16];

 char copyArray(unsigned char* state, unsigned char* key)
{

    for (int i = 0; i < 16; i++)
    {
        state[i] ^= key[i];
         // c[i] =  state[i];      // this gave me the address
        printf("%02x", state[i]);
    }
        printf("\n");

               memcpy (c, state,16);

    for (int i = 0; i < 16; ++i)
    {


        printf("%02d\n",c[i] );
    }
    printf("\n");

}

This function is executed 10 times in another function. What I am trying to achieve is to store the value of the last execution instead of the address

Answer 1

Thanks guys!

It is solved now. I made the c array unsigned, and that solved the problem

unsigned char c[16];

char copyArray(unsigned char* state, unsigned char* key)
{

for (int i = 0; i < 16; i++)
{
    state[i] ^= key[i];

    printf("%02x", state[i]);
}

printf("\n");

memcpy (c, state,16);

for (int i = 0; i < 16; ++i)
{
    printf("%02x\n",c[i] );
}
printf("\n");

}