[英]Writing Nested GraphQL Mutations
I am looking for examples of writing nested mutations. 我正在寻找编写嵌套突变的示例。 I am making a mutation for a recipe object and the schema looks like this:
我正在对配方对象进行更改,其架构如下所示:
const RecipeType = new GraphQLObjectType({
name: "Recipe",
fields: () => ({
id: { type: GraphQLID },
name: { type: GraphQLString },
dateCreated: { type: GraphQLString },
authorID: { type: GraphQLID },
prepTime: { type: PrepTimeType },
cookTime: { type: CookTimeType },
ingredients: { type: new GraphQLList(IngredientType) },
steps: { type: new GraphQLList(StepType) }
})
});
const PrepTimeType = new GraphQLObjectType({
name: "PrepTime",
fields: () => ({
quantity: { type: GraphQLFloat },
unit: { type: GraphQLString }
})
});
const CookTimeType = new GraphQLObjectType({
name: "CookTime",
fields: () => ({
quantity: { type: GraphQLFloat },
unit: { type: GraphQLString }
})
});
const IngredientType = new GraphQLObjectType({
name: "Ingredients",
fields: () => ({
name: { type: GraphQLString },
quantity: { type: GraphQLFloat },
unit: { type: GraphQLString }
})
});
const StepType = new GraphQLObjectType({
name: "Ingredients",
fields: () => ({
details: { type: GraphQLString },
estimatedTime: { type: GraphQLFloat },
unit: { type: GraphQLString }
})
});
I am looking to write a mutation that creates an entire object for this item. 我正在寻找写一个变异来创建该项目的整个对象。 The mutation looks like the following:
突变如下所示:
createRecipe: {
type: RecipeType,
args: {
// Required Args
name: { type: new GraphQLNonNull(GraphQLString) },
authorID: { type: new GraphQLNonNull(GraphQLID) },
ingredients: { type: new GraphQLList(IngredientType) },
steps: { type: new GraphQLList(StepType) },
// Not required args
prepTime: { type: PrepTimeType },
cookTime: { type: CookTimeType },
},
resolve(parent, args) {
let recipe = new Recipe({
name: args.name,
dateCreated: new Date().getTime(),
authorID: args.authorID,
ingredients: args.ingredients,
steps: args.steps
});
// Check for optional args and set to recipe if they exist
args.prepTime ? recipe.prepTime = args.prepTime : recipe.prepTime = null;
args.cookTime ? recipe.cookTime = args.cookTime : recipe.cookTime = null;
return recipe.save();
}
}
I am not sure how to create one mutation that creates the entire object. 我不确定如何创建一个可以创建整个对象的突变。 and then updating will be a further challenge.
然后更新将是进一步的挑战。 Does anyone have any examples or links to the docs that support this?
是否有人有任何示例或指向支持此操作的文档的链接? From what I can tell GraphQL hasn't covered this in a helpful manner.
据我所知,GraphQL并未以有用的方式进行介绍。
I am currently getting the following errors: 我目前遇到以下错误:
{
"errors": [
{
"message": "The type of Mutation.createRecipe(ingredients:) must be Input Type but got: [Ingredients]."
},
{
"message": "The type of Mutation.createRecipe(steps:) must be Input Type but got: [Steps]."
},
{
"message": "The type of Mutation.createRecipe(prepTime:) must be Input Type but got: PrepTime."
},
{
"message": "The type of Mutation.createRecipe(cookTime:) must be Input Type but got: CookTime."
}
]
}
Any support would be greatly appreciated. 任何支持将不胜感激。
Cheers, 干杯,
I figured this out. 我想通了。 I needed to create input types for each subdocument.
我需要为每个子文档创建输入类型。 I already had the object types but for the mutations, I had to add new ones.
我已经有了对象类型,但是对于突变,我不得不添加新的对象类型。 From there I placed it into the mutation as such.
从那里,我将其放入突变体中。
createRecipe: {
type: RecipeType,
args: {
// Required Args
name: { type: new GraphQLNonNull(GraphQLString) },
authorID: { type: new GraphQLNonNull(GraphQLID) },
ingredients: { type: new GraphQLList(IngredientInputType) },
steps: { type: new GraphQLList(StepInputType) },
// Not required args
prepTime: { type: PrepTimeInputType },
cookTime: { type: CookTimeInputType },
},
resolve(parent, args) {
let recipe = new Recipe({
name: args.name,
dateCreated: new Date().getTime(),
authorID: args.authorID,
ingredients: args.ingredients,
steps: args.steps
});
// Check for optional args and set to recipe if they exist
args.prepTime ? recipe.prepTime = args.prepTime : recipe.prepTime = null ;
args.cookTime ? recipe.cookTime = args.cookTime : recipe.cookTime = null ;
return recipe.save();
}
},
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