[英]Python - how does the variable affect the loop
I am wondering why there is a different result when I change from arr[n] in version 1 to n in version 2: 我想知道为什么从版本1的arr [n]更改为版本2的n时为什么会有不同的结果:
Version 1 版本1
def summer_69(arr):
list_sum2 = 0
n = 0
for arr[n] in range(arr[n] == 6, (arr[n]== 9) + 1):
list_sum2 += arr[n]
print(list_sum2)
summer_69([1, 3, 5])
summer_69([4, 5, 6, 7, 8, 9])
Result for Version 1 版本1的结果
0
0
Version 2 版本2
def summer_69(arr):
list_sum2 = 0
n = 0
for n in range(arr[n] == 6, (arr[n]== 9) + 1):
list_sum2 += arr[n]
print(list_sum2)
summer_69([1, 3, 5])
summer_69([4, 5, 6, 7, 8, 9])
Result for Version 2 第2版的结果
1
4
that's not how range works. 范围不是这样的。
in this line: 在这一行:
for n in range(arr[n] == 6, (arr[n]== 9) + 1):
arr[n] == 6
and (arr[n]== 9) + 1
are returning truth values because ==
is a comparison operator so n
here at best takes values 0 or 1. arr[n] == 6
和(arr[n]== 9) + 1
返回的是真值,因为==
是一个比较运算符,因此n
最多为0或1。
you want 你要
for n in range(6, 10):
so that the value of n
iterates from 6 to 9, range()
being inclusive to the left and exclusive to the right 因此
n
的值从6迭代到9, range()
在左边是包含的,在右边是排斥的
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