如何将字符串中的连续字母和连续数字分别合并到列表中？

Question

Say I have the following string:

    string1 = 'Twenty 20 Twelve 12'

I would like to convert it into a list that would keep words as strings in separate elements, and numbers in another (as integers):

    list1 = ['Twenty', 20, 'Twelve', 12]

My current code looks is:

    list1 = [y for y in string1.replace(' ','')]

and the result prints out as:

    ['T','w','e','n','t','y','2','0','T','w','e','l','v','e','1','2']

How would I be able to write a code to keep words in separate entries, and turn numbers inside the string into integers in the list? I am a beginner to programming who is currently learning Python in parallel with C.

Answer 1

Look into the .split() function.

It takes the form of

str.split(sep=None, maxsplit=-1)

so you want your code to look like this to break it apart.

string1 = 'Twenty 20 Twelve 12'
string1.split()
#['Twenty', '20', 'Twelve', '12']

To convert the numbers to integers, just check for .isdigit()

[int(i) if i.isdigit() else i for i in string1.split()]
#['Twenty', 20, 'Twelve', 12]

if you're not familiar with list comprehensions , this is analogous to

values = []
for i in string1.split():
    if i.isdigit():
        values.append(int(i))
    else:
        values.append(i)

values
#['Twenty', 20, 'Twelve', 12]

Answer 2

You really should google it....

but you can use split

string1 = 'Twenty 20 Twelve 12'
list1=string1.split(' ')