如何将正则表达式转换为列表

Question

I've got a regexp string with only | and () like :

(Hello|Hi) my name is (Bob|Robert)

And I would like to have the complete list of string who match the regexp :

Hello my name is Bob Hello my name is Robert Hi my name is Bob Hi my name is Robert

Is it a tool (librairy) who already do this ?

My first problem is to split the regexp string into a array of array like :

[['Hello','Hi'],'my name is' ,['Bob','Robert']]

Answer 1

Try exrex, think that should work for you

Simple script

import exrex
print(list(exrex.generate('(Hello|Hi) my name is (Bob|Robert)')))

Output

→ python new_test.py
['Hello my name is Bob', 'Hello my name is Robert', 'Hi my name is Bob', 'Hi my 
name is Robert']

https://github.com/asciimoo/exrex

Answer 2

Do it with regex:-)

re.split(r"(\(.+?\|.+?\))",s)
Out: ['', '(Hello|Hi)', ' my name is ', '(Bob|Robert)', '']
# and for each string in the list:
re.split(r"\((.+?)\|(.+?)\)",'(Hello|Hi)')
Out: ['', 'Hello', 'Hi', '']

Answer 3

You can try below solution, here I haven't imported any module. The only functions used are strip, split and replace

input_string = "(Hello|Hi) my name is (Bob|Robert)"
split_string = (input_string.replace("("," ").replace(")"," ")).split("  ")
print ([i.strip().split("|") for i in split_string])

#Output --> [['Hello', 'Hi'], ['my name is'], ['Bob', 'Robert']]

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I hope this helps!

---

If you need the final solution to your query then use below code:

from itertools import product
input_string = "(Hello|Hi) my name is (Bob|Robert)"
split_string = (input_string.replace("("," ").replace(")"," ")).split("  ")
jj = [i.strip().split("|") for i in split_string]
kk = list(product(*jj))
print ([" ".join(i) for i in kk])
#output --> ['Hello my name is Bob', 'Hello my name is Robert', 'Hi my name is Bob', 'Hi my name is Robert']

The above code will also work for: input_string = "(Hello|Hi|Hey) my (name|naam) is (Bob|Robert)"