数组中日期的最小/最大

Question

 var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"]; var sorted = expenseDates.slice() .sort(function(a, b) { return new Date(a) - new Date(b); }); console.log(sorted.pop()+ '--max'); console.log(sorted.shift()+ '--min'); 

Answer 1

You don't have convert it into date object as the date are in YYYY-MM-DD format which itself is in sorted order by year => month => day . So you just have to compare the input string as localCompare . First index is minimum date while the last index is maximum date

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

    expenseDates = expenseDates.sort(function(a, b) {
        return a.localeCompare(b);
    });

   console.log('--min => ',expenseDates[0]);
   console.log('--max => ', expenseDates[expenseDates.length -1]);

Working jsFiddle demo - https://jsfiddle.net/rpdon5cm/1/