[英]I want output None instead of 0
def second_largest(numbers):
first, second = 0,0
for n in numbers:
if n > first:
first, second = n, first
elif first > n > second:
second = n
return second
print(second_largest([2,2,2]))
I want to output by None not 0 if there is no second largest number and also if there is empty list. 如果没有第二大数字并且也有空列表,我想输出None不为0。
尝试更改返回行以return second or None
。
A little tweak in return statement will do. 在return语句中稍作调整即可。 Check out the below code:
查看以下代码:
def second_largest(numbers):
first, second = 0,0
for n in numbers:
if n > first:
first, second = n, first
elif first > n > second:
second = n
return None if second ==0 else second
print(second_largest([2,2,2]))
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