查找并替换字符串中的单词

Question

#include <iostream>
#include <cstring>
using namespace std;

int main()
{
   char str[80];
   char find[10];
   char change[10];
   char* pstr;
   char* temp = new char[80];
   cin.getline(str, 80);
   cin.getline(find,10);
   cin.getline(change,10);

   pstr =strstr(str,find);

     int a = str.find(pstr);
     int len;
     len = strlen(find);
     str.replace(a,len,change);



   delete []temp;
   cout<< str<< endl;
   return 0;
}   

The error message is:

 Main.cpp: In function 'int main()': Main.cpp:18:15: error: request for member 'find' in 'str', which is of non-class type 'char [80]' int a = str.find(pstr); ^ Main.cpp:21:7: error: request for member 'replace' in 'str', which is of non-class type 'char [80]' str.replace(a,len,change); ^ 

For example,

what is your nam / nam / name

the output is

'what is your name'
what is matter?

Answer 1

The statement str.find(pstr); means Call the member function find of the object str with pstr as argument . If you are not sure to completely understand this sentence, I'd suggest you to find a good C++ book .

The thing is, str has type char[80] , which is not an object of class-type with an available member function find . It's a C-style array, not suitable for OOP.

What you need is std::string :

#include <string>

std::string str;
/* set str */
auto pos = str.find(pstr);

Here is the doc of std::string::find() .

Answer 2

Use std::string instead of char[N] .

The char[80] type is a fundamental type and doesn't have functions.

For the getline, you will need to change it to:

std::getline(std::cin, str);

Answer 3

int main()
{
   char str[80];
   char find[10];
   char change[10];
   char* pstr;
   char* temp = new char[80];
   cin.getline(str, 80);
   cin.getline(find,10);
   cin.getline(change,10);

   pstr = strstr(str,find);

   std::string newStr = str;
     int a = newStr.find(pstr);
     int len;
     len = strlen(find);
     newStr.replace(a,len,change);

  delete []temp;
   cout<< newStr << endl;
   return 0;
}