Shell脚本以打印具有定界符的变量

Question

I have a shell script, which gets bunch of values. I am segregating it based on a Delimiter(,). Now i want to print it one by one inside a for loop. For Eg

var=/a/b/c,d/e/f/,x/y/z
for i in $(echo $var | sed "s/,/ /g")
do
echo $i
done 

Output is coming empty, Expected output is

/a/b/c
d/e/f/
x/y/z

Answer 1

You don't need a loop.

sed 's/,/\n/g' <<< "$var"
sed 'y/,/\n/' <<< "$var"
tr ',' '\n' <<< "$var"
echo "${var//,/$'\n'}"

they all yield the desired output.

Answer 2

Just to add another option -

var="/a/b/c,d/e/f/,x/y/z"
while IFS=, read a b c
do printf "a=$a b=$b c=$c\n"
done <<< "$var"
a=/a/b/c b=d/e/f/ c=x/y/z

Doesn't need a loop - works fine as

$: IFS=, read a b c <<< "$var"
$: printf "a=$a b=$b c=$c\n"
a=/a/b/c b=d/e/f/ c=x/y/z

... just wanted to show the loop structure in case it helped.

Answer 3

You could read it into an array. This is quite readable:

var=/a/b/c,d/e/f/,x/y/z
IFS=, read -a paths <<<"$var"
for p in "${paths[@]}"; do echo "$p"; done

/a/b/c
d/e/f/
x/y/z