从包含多个对象的数组中返回编号最高的对象

Question

I was able to figure out how to return the highest number from a associative array with multiple objects. But I need the whole object.

I prepared this example:

 var data = [ { nr: 235, text: "foo" } ,{ nr: 351, text: "bar" } ]; var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) { return data[e]['nr']; })); var index = "???"; console.log("Highest 'nr': " + highestNr); console.log("Index at nr "+ highestNr + ": " + index); //console.log(data[index]); 

I need the index or the whole object. I need to show the text from the object with the highest number.

Answer 1

You could reduce the array by selecting the one with a greater value.

 var data = [{ nr: 235, text: "foo" }, { nr: 351, text: "bar" }], topNr = data.reduce((a, b) => a.nr > b.nr ? a : b); console.log(topNr); 

Answer 2

You can "sort" the array by "nr" property in descending order and get first element "[0]"

 var data = [ { nr: 235, text: "foo" } ,{ nr: 351, text: "bar" } ]; // slice added so that original data is not mutated var result = data.slice(0).sort((a,b) => b.nr - a.nr)[0] console.log(result) 

Answer 3

You can also use findIndex() method:

 var data = [ { nr: 235, text: "foo" } ,{ nr: 351, text: "bar" } ]; var highestNr = Math.max.apply(null, Object.keys(data).map(function(e) { return data[e]['nr']; })); var index = data.findIndex(function(ln) { return ln.nr === highestNr; }); console.log("Highest 'nr': " + highestNr); console.log("Index at nr "+ highestNr + ": " + index); //console.log(data[index]);