我将如何解析 c 中的字符串并忽略该字符串中的某个单词？
[英]How would I parse strings in c and ignore a certain word in that string?
问题描述
How would I parse strings in c to ignore certain characters?
我将如何解析 c 中的字符串以忽略某些字符？
Say I have code that contains the word, "contain", so basically:假设我有包含单词“包含”的代码，所以基本上：
contains blah sdkld sldksdk
contains dksld sldkd tkel
So basically, I want to get:所以基本上，我想得到：
blah sdkld sldksdk
dksld sldkd tkel
1 个解决方案
解决方案1
-2 2018-11-14 05:53:02
you can split word, later eval the val return:您可以拆分单词，稍后评估 val 返回：
http://c.conclase.net/librerias/?ansifun=strtok http://c.conclase.net/librerias/?ansifun=strtok
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