从列表列表创建许多列表

Question

i have created a list of lists through list comprehension and would like to unravel this list of lists into many lists through iteration (with the variable name of each list iterating aswell), is that possible? as to what exactly i mean by that i want:

listoflists = [[1,2,3],[2,3,4],[3,4,5,6,7],["a","b"]]

with the output being:

list1=[1,2,3]
list2=[2,3,4]
list3=[3,4,5,6,7]
list4=["a","b"]

so i not only get the unraveled lists but also the names of each list iterating with range(len(listoflists)).

For clarification as to why i need this, for my project i want to write a csv file with each column containing one of those lists.

Answer 1

Consider forming a dictionary, where your separate lists are captured in the key-value pairs:

>>> manylists = {f'list{i}': j for i, j in enumerate(listoflists, 1)}
>>> manylists
{'list1': [1, 2, 3], 'list2': [2, 3, 4],
 'list3': [3, 4, 5, 6, 7], 'list4': ['a', 'b']}

This roughly mimics the "dynamic variable creation" that you are trying to do, but instead of all of those lists floating around in your local namespace, they are all wrapped up in one neat data structure (a dictionary), called manylists .

You can also use simply dict(enumerate(listoflists, 1)) , where the resulting keys will be ints starting at 1 and ascending from there.

Answer 2

You can iterate in your list of list with a simple for

for list in listoflists:

And then print it in the format you want.