sql查询，包括不更新表在哪里呢？

Question

    <?php
session_start();


error_reporting(0);
include("config.php");
?>
<?php echo '<pre>' . print_r($_SESSION, TRUE) . '</pre>'; ?>

    <html>
    <head>
      <title>MR stempagina</title>
    </head>
    <body>
      <?php if( $_SESSION['user_info']['gestemd']>0){
        header("Location: logout.php");
      }
      ?>

      <?php echo $_SESSION['user_info']['name']  ?>, u kunt hier stemmen. 
      <form action="stemmen.php" method="POST">
        <p>Welke ouder wilt u als vertegenwoordiger van de ouders van de HBK afdeling in de medezeggenschapsraad?</p>
        <input type="radio" name="kandidaat" value="piet"> piet<br>
        <input type="radio" name="kandidaat" value="hein"> hein<br>
        <p><input type="submit" name="stem" value="stem"></p>

<?php

$error = '';
  if(isset($_POST['kandidaat'])){
      echo $_POST['kandidaat'];
      $_SESSION['user_info'] = $user;
      //$query = " UPDATE ".$SETTINGS["USERS"]." SET gestemd = gestemd+1 WHERE id=".$_SESSION['id'];
      //$query = " UPDATE ".$SETTINGS["USERS"]." SET gestemd = gestemd+1";
      //$query = " UPDATE ".$SETTINGS["kandidaat"]." SET aantal = aantal+1";
      //$query = " UPDATE ".$SETTINGS["USERS"]." SET gestemd = gestemd+1 WHERE id='{$_SESSION['id']}'";
      $query = "UPDATE {$SETTINGS["USERS"]} SET gestemd = gestemd+1 WHERE id={$_SESSION['id']}";
      mysql_query ($query, $connection ) or die ('request "Could not execute SQL query" '.$query . ': ' . mysql_error());


    }

?>

          </form>
    </body>
    </html>

when i use: 当我使用时：

$query = " UPDATE ".$SETTINGS["USERS"]." SET gestemd = gestemd+1 WHERE id='{$_SESSION['id']}'";

the table_column gestemd is not incremented. table_column gestemd不增加。

when i use the same query without the where it works but increment of course all users. 当我使用相同的查询而没有它在哪里工作，但当然增加所有用户。

The printR is and echo is for debugging. printR和echo用于调试。

thx for your help 谢谢你的帮助

Answer 1

i found The answer to the asked question 我找到了问题的答案

$query = " UPDATE ".$SETTINGS["USERS"]." SET gestemd = gestemd+1 WHERE id={$_SESSION['user_info']['id']}"; $ query =“ UPDATE”。$ SETTINGS [“ USERS”]。“ SET gestemd = gestemd + 1 WHERE id = {$ _ SESSION ['user_info'] ['id']}”;

with this solution it works. 通过这种解决方案，它可以工作。

sql查询，包括不更新表在哪里呢？

问题描述

1 个解决方案

解决方案1
0 2018-11-15 16:02:34

sql查询，包括不更新表在哪里呢？

问题描述

1 个解决方案

解决方案1 0 2018-11-15 16:02:34

解决方案1
0 2018-11-15 16:02:34