用于从父字符串中识别和提取两个不同字符串的正则表达式

Question

I have the following string: your lead count is @_sfdc.Account.phonenumber.value, you are having @_hrms.leaves.leavescount per year .

From this, I want to fetch @_sfdc.Account.phonenumber.value and @_hrms.leaves.leavescount . It should fetch all dot separated stings even if we have more than one like in this case.

Currently I have tried with this regex: /@_sfdc.([a-zA-Z]).+/g;

Answer 1

/@_[\\w\\.]+/g

这与“ @_”匹配，后跟字母，数字或点（ . ）的任何序列。

Answer 2

You were on the right path, almost there! The main error here is that . is a reserved character in a regex which means "any character". To actually match a dot character, you need to escape it with a backslash: \\.

So, your regex becomes /@_sfdc\\.([a-zA-Z])\\.+/g

Another thing to notice is that you want to match letters and dots in the same group, while your current expression requires the match to end with a dot. So, let's move that dot inside the matching group square brackets: /@_sfdc\\.([a-zA-Z\\.])+/g .

Also you say that you want to match both the @_sfdc and @_hrms prefixes, so let's change that. There are two ways to do this:

• looking specifically for @_sfdc and @_hrms : /@_(sfdc|hrms)\\.([a-zA-Z\\.])+/g
• or matching any string that starts with @_ : /@_([a-zA-Z\\.])+/g . In this case, hrms. and sfdc. are captured by the same block that captures the rest of the string ( [a-zA-Z\\.]+ )