[英]C# Json.Net Deserialize Json with different “key” parameter
I am trying to deserialize JSON using the Json.NET library. 我正在尝试使用Json.NET库反序列化JSON。 JSON which I receive looks like: 我收到的JSON如下所示:
{
"responseHeader": {
"zkConnected": true,
"status": 0,
"QTime": 2
},
"suggest": {
"mySuggester": {
"Ext": {
"numFound": 10,
"suggestions": [
{
"term": "Extra Community",
"weight": 127,
"payload": ""
},
{
"term": "External Video block",
"weight": 40,
"payload": ""
},
{
"term": "Migrate Extra",
"weight": 9,
"payload": ""
}
]
}
}
}
}
The problem is that the "Ext" that you can see in it is part of the parameter passed in the query string and will always be different. 问题在于您可以在其中看到的“ Ext”是在查询字符串中传递的参数的一部分,并且始终是不同的。 I want to get only the values assigned to the term "term". 我只想获取分配给术语“项”的值。
I tried something like this, but unfortunately does not works: 我尝试了类似的方法,但不幸的是它不起作用:
public class AutocompleteResultsInfo
{
public AutocompleteResultsInfo()
{
this.Suggest = new Suggest();
}
[JsonProperty("suggest")]
public Suggest Suggest { get; set; }
}
public class Suggest
{
[JsonProperty("mySuggester")]
public MySuggesterElement MySuggesterElement { get; set; }
}
public struct MySuggesterElement
{
public MySuggester MySuggester;
public string JsonString;
public static implicit operator MySuggesterElement(MySuggester MySuggester) =>new MySuggesterElement { MySuggester = MySuggester };
public static implicit operator MySuggesterElement(string String) => new MySuggesterElement { JsonString = String };
}
public class MySuggester
{
[JsonProperty("suggestions")]
public Suggestions[] Suggestions { get; set; }
}
public class Suggestions
{
[JsonProperty("term")]
public string Autocopmplete { get; set; }
}
internal class SuggesterElementConverter : JsonConverter
{
public override bool CanConvert(Type t)
{
return t == typeof(MySuggesterElement) || t == typeof(MySuggesterElement?);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
switch (reader.TokenType)
{
case JsonToken.String:
case JsonToken.Date:
var stringValue = serializer.Deserialize<string>(reader);
return new MySuggesterElement { JsonString = stringValue };
case JsonToken.StartObject:
var objectValue = serializer.Deserialize<MySuggester>(reader);
return new MySuggesterElement { MySuggester = objectValue };
}
throw new Exception("Cannot unmarshal type MySuggesterElement");
}
public override void WriteJson(JsonWriter writer, object untypedValue, JsonSerializer serializer)
{
var value = (MySuggesterElement)untypedValue;
if (value.JsonString != null)
{
serializer.Serialize(writer, value.JsonString);
return;
}
if (value.MySuggester != null)
{
serializer.Serialize(writer, value.MySuggester);
return;
}
throw new Exception("Cannot marshal type CollationElements");
}
public static readonly SuggesterElementConverter Singleton = new SuggesterElementConverter();
}
public class AutocompleteConverter
{
public static readonly JsonSerializerSettings Settings = new JsonSerializerSettings
{
MetadataPropertyHandling = MetadataPropertyHandling.Ignore,
DateParseHandling = DateParseHandling.None,
Converters =
{
SuggesterElementConverter.Singleton
}
};
}
var results = JsonConvert.DeserializeObject<AutocompleteResultsInfo>(resultJson, AutocompleteConverter.Settings);
Many thanks for your help. 非常感谢您的帮助。
Kind Regerds, Wojciech 亲切的问候,Wojciech
You could decode the "mySuggester" as a dictionary: public class Suggest 您可以将“ mySuggester”解码为字典:public class建议
public class Suggest
{
[JsonProperty("mySuggester")]
public Dictionary<string, MySuggester> MySuggester { get; set; }
}
Then you'll be able to access the suggestions with the query string parameter: 然后,您可以使用查询字符串参数访问建议:
var variablePropertyName = "Ext";
var result = JsonConvert.DeserializeObject<AutocompleteResultsInfo>(_json);
var suggestions = result.Suggest.MySuggester[variablePropertyName].Suggestions;
if you don't know the property name you could also look it up in the dictionary: 如果您不知道属性名称,也可以在字典中查找它:
var variablePropertyName = result.Suggest.MySuggester.Keys.First();
Working example: https://dotnetfiddle.net/GIKwLs 工作示例: https : //dotnetfiddle.net/GIKwLs
If you don't need to deserialize the whole json string you can use a JsonTextReader. 如果您不需要反序列化整个json字符串,则可以使用JsonTextReader。 Example: 例:
private static IEnumerable<string> GetTerms(string json)
{
using (JsonTextReader reader = new JsonTextReader(new StringReader(json)))
{
while (reader.Read())
{
if (reader.TokenType == JsonToken.PropertyName && reader.Value.Equals("term"))
{
string term = reader.ReadAsString();
yield return term;
}
}
}
}
Using the code: 使用代码:
string json = @"{
""responseHeader"": {
""zkConnected"": true,
""status"": 0,
""QTime"": 2
},
""suggest"": {
""mySuggester"": {
""Ext"": {
""numFound"": 10,
""suggestions"": [
{
""term"": ""Extra Community"",
""weight"": 127,
""payload"": """"
},
{
""term"": ""External Video block"",
""weight"": 40,
""payload"": """"
},
{
""term"": ""Migrate Extra"",
""weight"": 9,
""payload"": """"
}
]
}
}
}
}";
IEnumerable<string> terms = GetTerms(json);
foreach (string term in terms)
{
Console.WriteLine(term);
}
If you only need the object containing the term, and nothing else, you could work with the JSON values directly by using the JObject
interface in JSON.Net. 如果只需要包含术语的对象,而无需其他,则可以通过使用JObject
中的JObject
接口直接使用JSON值。
var parsed = JObject.Parse(jsonString);
var usingLinq = (parsed["suggest"]["mySuggester"] as JObject)
.Descendants()
.OfType<JObject>()
.Where(x => x.ContainsKey("term"));
var usingJsonPath = parsed.SelectTokens("$.suggest.mySuggester.*.*[?(@.term)]")
.Cast<JObject>();
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