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如何通过 kotlin 中的序数值获得枚举成员?

[英]How can I get a enum member by the ordinal value in kotlin?

I know I can get the ordinal value of a enum member using the code Color.BLUE.ordinal .我知道我可以使用代码Color.BLUE.ordinal获取枚举成员的序号值。

Now I hope to get Color.Green when I know the ordinal value of a enum member, how can I do?现在我希望在知道枚举成员的序号值时得到 Color.Green,我该怎么办?

Code代码

enum class Color{
    RED,BLACK,BLUE,GREEN,WHITE
}



var aOrdinal=Color.BLUE.ordinal //it's 2

val bOrdinal=3  //How can I get Color.Green

Just use values() function which will return the Array of enum values and use ordinal as an index只需使用values()函数,它将返回枚举值数组并使用序数作为索引

Example例子

val bOrdinal=3

val yourColor : Color = Color.values()[bOrdinal]

👷 Safety first: 👷 安全第一:

// Default to null
val color1: Color? = Color.values().getOrNull(bOrdinal)

// Default to a value
val color2: Color = Color.values().getOrElse(bOrdinal) { Color.RED }

You can use Kotlin enumValues<>() to get it您可以使用 Kotlin enumValues<>()来获取它

Example例子

    enum class Color{
    GREEN,YELLOW
}

fun main(str:Array<String>){
    val c  = enumValues<Color>()[1]
   print("Color name is ${c.name} and ordinal is ${c.ordinal}")
}

Prints "Color name is YELLOW and ordinal is 1"打印“颜色名称为黄色,序数为 1”

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