如果tk.Toplevel在其他文件中，如何关闭窗口

Question

how do I close my current window if I can't see the tk.Toplevel(root) from the method I am in?

Here a small example of what i mean:

file1.py:

import Tkinter as tk
import file2
class ExampleMain:
    def __init__(self, root):
        self.mainFrame = tk.Frame(root)
        ...
        tk.Button(self.mainFrame, command=self.button_pressed)
        ...

    def button_pressed(self):
        self.whatever = tk.Toplevel(root)
        self.app = file2.ExampleNotMain(self.whatever)

if __name__ == '__main__':
    root = tk.Tk()
    app = ExampleMain(root)
    root.mainloop()

file2.py:

import tkinter as tk
class ExampleNotMain:
    def __init__(self, root):
        self.frame = tk.Frame(root)
        ...
        tk.Button(self.frame, command=self.close_window)
        ...

    def close_window(self):
        =>  missing_command_here

In this example I would like to close the second window created (and keep the first).

If all the code is in one file something like

self.whatever.destroy()

would do it. My problem is I can't see the object from the first file with the command being in the second file.

I found something like

execfile("file2.py") 

but I don't like that solution.

Is there a better way to solve my problem?

I would realy apriciate your help. Thanks in advance.

Answer 1

When you create ExampleNotMain, you pass the 2nd Toplevel self.whatever. In ExampleNotMain.__init__ , it gets bound to root . ( master or parent would be a better parameter name). In __init__ , add self.top = root (or whatever you call the passed-in toplevel). In (or whatever you call the passed-in toplevel). In close_window , add self.top.destroy()`.