如何使用for循环和拼接来删除单词，然后检查数组中的特定单词

Question

I want to make a function that looks for a specific name (Inger) in an array, and the removes that name. Then I want the function to tell that a name doesn't exist in the array.

    var femaleName = ["Anne","Inger","Kari","Marit","Ingrid"]

    function removeElement (aTable, aName) {

        for (var i = 0; i <= aTable.length - 1; i++) {
            if (aTable[1] === aName) {

                aTable.splice(i, 1)
                document.write(aTable); {break;}

            } else if (aTable[i] !== aName) {
                document.write(aName + " is not in the list");
            }
        }
    }

I've tried to solve it this way, but I don't get it right. The output should be something like this:

Anne, Kari, Marit, Ingrid
Victoria is not in the list

Answer 1

Do you have to write functions? Javascript has Array methods to do this for you.

Array.prototype.filter()

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

includes()

The includes() method determines whether an array includes a certain element, returning true or false as appropriate.

 var femaleName = ["Anne", "Inger", "Kari", "Marit", "Ingrid"] femaleName = femaleName.filter(name => name !== 'Inger') console.log(femaleName); console.log(femaleName.includes('Inger')); 

Answer 2

The issue is this line:

if (aTable[1] === aName) {

That only checks the second index ( "Inger" ). It should be this:

if (aTable[i] === aName) {

Answer 3

You could do this:

function removeElement(aTable, aName) {
    const index = aTable.indexOf(aName);
    if (index > -1) {
        aTable.splice(index, 1);
        document.write(aTable);
    } else {
        document.write(aName + " is not in the list");
    }
}

Or you could always use functional Array.prototype.filter().

Answer 4

Following your description, try this example. That first gets the index in the array of the searched name using findIndex , then removes it from the array using splice and finally prints the result

 const names = ['Anne', 'Inger', 'Kari', 'Marit', 'Ingrid']; function notify(criteria) { const position = getPosition(criteria); const removed = removeName(position); console.log(names); console.log(`${removed} is not in the list`); } function getPosition(criteria) { return names.findIndex(name => name === criteria); } function removeName(position) { return names.splice(position, 1); } notify('Inger');