如何在PHP中操纵While循环的最终输出？

Question

I want to manipulate the end output of a while loop .

In this example, i am using number 5 in place of a variable.

<?php $i=1; while($i<=5)  {
echo "col-md-" . round(12/5) . "<br>";
$i++;
} ?>

giving output of

• col-md-2
• col-md-2
• col-md-2
• col-md-2

• col-md-2 ---> I want to show 4 here by applying the below math >>

  12-(5-1)*round(12/5)

Can you please help me with this. is it possible? A help will be very much appreciated.

Answer 1

One option could be to check if the variable $i equals 5 before it gets incremented:

$i=1;
while($i<=5)  {
    echo "col-md-" . round(12/5) . "<br>";

    if ($i === 5) {
        echo "col-md-" . (12-(5-1)*round(12/5));
    }
    $i++;
}

If it is always at the end, you can just add it after the while loop:

echo "col-md-" .  (12-(5-1)*round(12/5));

Answer 2

An alternative is to use a for() loop and end it one earlier and then output an extra column after...

$count = 5;   // Number of columns
for ( $i = 1; $i < $count; $i++ ) {
    echo "col-md-" . round(12/$count) . "<br>";
}
echo "col-md-" . (12-($count-1)*round(12/$count)) . "<br>";

Which gives...

col-md-2<br>col-md-2<br>col-md-2<br>col-md-2<br>col-md-4<br>

Answer 3

This is the final code, which solved my issue.

$count = 1; // Number of columns 
for ( $i = 1; $i < $count; $i++ ) { 
  echo "col-md-" . floor(12/$count) . "<br>"; 
} 

if (($count == 5 || 7 || 8 || 9 || 10 || 11)) { 
 echo "col-md-" . (12-($count-1)*floor(12/$count)) . "<br>"; 
} 

Thanks to @nigel and @thefourthbird.