如何绘制用熊猫除以一列得到的5个最大值？

Question

I have a dataset that looks like this:

variety|points|price  
a      |  80  |  5  
b      |  85  |  6  
b      |  70  |  8  

and so on.

I would like to create a barplot using seaborn that has variety on the x-axis and points/price ratio on the y-axis. I have about 150k rows, so I only want to display the 5 best points/price ratios.

This was my idea using another column called result:

df["Result"] = df["points"]/df["price"]
ax = sns.barplot(x="variety", data=df, order=df["Result"].iloc[:5].index)

which does not work.

I will be glad for any advice.

Answer 1

You could try to filter out the first 5 largest values using nlargest .

largest_five= df.nlargest(5,'Result')

Then plot it

ax = sns.barplot(x="variety",y='Result', data=largest_five)

Let me know if this works.