[英]MySQL error while trying to create table,
I'm using PHPMyAdmin, hosted with hostgator, to add a table to a database, but I keep getting the following error: 我正在使用与hostgator一起托管的PHPMyAdmin来向数据库添加表,但是我一直收到以下错误:
note
TEXT NOT NULL , cardNumber
BIGINT(20) NOT NULL , `nameC' at line 1 note
TEXT NOT NULL, cardNumber
BIGINT(20)NOT NULL,`nameC'在第1行 Here's what I have: 这就是我所拥有的:
and here's the preview of the SQL
这是SQL的预览
CREATE TABLE `nightwin_mark-inn`.`guests` (
`id` INT(3) NOT NULL AUTO_INCREMENT ,
`dateIn` DATE NOT NULL ,
`dateOut` DATE NOT NULL ,
`email` TEXT NOT NULL ,
`phone` INT(10) NOT NULL ,
`room` TINYINT(2) NOT NULL ,
`price` DOUBLE(6) NOT NULL ,
`note` TEXT NOT NULL ,
`cardNumber` BIGINT(20) NOT NULL ,
`nameCard` TEXT NOT NULL ,
`expDate` TEXT NOT NULL ,
`cvc` TINYINT(3) NOT NULL ,
PRIMARY KEY (`id`)
)
What's causing this issue? 是什么导致了这个问题? Do I have the length of one of the fields wrong?
我有一个字段的长度错了吗?
Try to use this 试着用这个
price` DOUBLE(6,2) NOT NULL //9999.99 max value stored
instead of 代替
price` DOUBLE(6) NOT NULL
Note: for price field use datatype DECIMAL more preferable.
注意:对于价格字段,使用数据类型DECIMAL更为可取。 In FLOAT or DOUBLE datatype you will get rounding number issue
在FLOAT或DOUBLE数据类型中,您将获得舍入数字问题
You can try below - DOUBLE(6)
should be only DOUBLE
您可以在下面尝试 -
DOUBLE(6)
应该只有DOUBLE
CREATE TABLE `nightwin_mark-inn`.`guests` ( `id` INT(3) NOT NULL AUTO_INCREMENT ,
`dateIn` DATE NOT NULL , `dateOut` DATE NOT NULL , `email` TEXT NOT NULL ,
`phone` INT(10) NOT NULL , `room` TINYINT(2) NOT NULL , `price` DOUBLE NOT NULL ,
`note` TEXT NOT NULL , `cardNumber` BIGINT(20) NOT NULL , `nameCard` TEXT NOT NULL ,
`expDate` TEXT NOT NULL , `cvc` TINYINT(3) NOT NULL , PRIMARY KEY (`id`))
please try using this MySQL statement
CREATE TABLE `guests` ( `id` INT(3) NOT NULL AUTO_INCREMENT , `dateIn` DATE NOT NULL , `dateOut` DATE NOT NULL , `email` TEXT NOT NULL , `phone` INT(10) NOT NULL , `room` TINYINT(2) NOT NULL , `price` DOUBLE(6,2) NOT NULL , `note` TEXT NOT NULL , `cardNumber` BIGINT(20) NOT NULL , `nameCard` TEXT NOT NULL , `expDate` TEXT NOT NULL , `cvc` TINYINT(3) NOT NULL , PRIMARY KEY (`id`));
please try using this MySQL statement 请尝试使用此MySQL语句
CREATE TABLE guests
( id
INT(3) NOT NULL AUTO_INCREMENT , dateIn
DATE NOT NULL , dateOut
DATE NOT NULL , email
TEXT NOT NULL , phone
INT(10) NOT NULL , room
TINYINT(2) NOT NULL , price
DOUBLE(6,2) NOT NULL , note
TEXT NOT NULL , cardNumber
BIGINT(20) NOT NULL , nameCard
TEXT NOT NULL , expDate
TEXT NOT NULL , cvc
TINYINT(3) NOT NULL , PRIMARY KEY ( id
)); CREATE TABLE
guests
( id
INT(3)NOT NULL AUTO_INCREMENT, dateIn
DATE NOT NULL, dateOut
DATE NOT NULL, email
TEXT NOT NULL, phone
INT(10)NOT NULL, room
TINYINT(2)NOT NULL, price
DOUBLE(6,2) )NOT NULL, note
TEXT NOT NULL, cardNumber
BIGINT(20)NOT NULL, nameCard
TEXT NOT NULL, expDate
TEXT NOT NULL, cvc
TINYINT(3)NOT NULL,PRIMARY KEY( id
));
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.