简体   繁体   English

SQL组按星期几日期并获得计数

[英]SQL Group dates by day of week and get count

I have a table with a bunch of dates in it and I need to convert those dates to what day of the week it is and then group them. 我的桌子上有一堆日期,我需要将这些日期转换成星期几,然后将它们分组。

Example output looks like 示例输出看起来像

+------------+-------+
|    Date    | Count |
+------------+-------+
| 11/12/2018 |     1 |
| 11/19/2018 |     2 |
| 11/20/2018 |     1 |
| 11/21/2018 |     2 |
+------------+-------+

The output that I would like would be 我想要的输出是

+-----------+-------+
|  DayName  | Count |
+-----------+-------+
| Monday    |     3 |
| Tuesday   |     1 |
| Wednesday |     2 |
+-----------+-------+

Im just unsure on how to rename the dates to the day of the week and have them group together. 我只是不确定如何将日期重命名为星期几并将它们组合在一起。

Use the datename function to extract the weekday "name": 使用datename函数提取工作日的“名称”:

SELECT DATENAME(WEEKDAY, Date), COUNT(*)
FROM t
GROUP BY DATENAME(WEEKDAY, Date)

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM