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返回布尔值

[英]Return the boolean value

I have to write such a program: 1.two two-dimensional arrays have the same dimensions m × n, 2.satisfy the condition that aij = bij for i = 0,. 我必须编写这样一个程序:1.两个二维数组具有相同的维数m×n,2.满足aij = bij且i = 0的条件。 . . , m and j = 0,. ,m和j = 0 ,。 . . , n The method returns the result in the form of a logical value true only when both of the above are met simultaneously. ,n仅当同时满足以上两个条件时,该方法才以逻辑值true的形式返回结果。 what does it mean "returns the result"? “返回结果”是什么意思? This means that it displays on the screen? 这意味着它显示在屏幕上吗? I wrote something like that: 我写了这样的东西:

static boolean isEqual(int[][] a, int[][] b) {
    int ia = 0;`
    int ib = 0;
    int ja = 0;
    int jb = 0;
    boolean equal=true;
    for (int i = 0; i < a.length; i++) {
        for (int j = 0; j < a[i].length; j++) {

            ia++;
        }
        ja++;
    }

    for (int i = 0; i < b.length; i++) {
        for (int j = 0; j < b[i].length; j++) {

            ib++;
        }
        jb++;
    }
    if (ia == ib && ja == jb) {
        for (int i = 0; i < b.length; i++) {
            for (int j = 0; j < b[i].length; j++) {
                if (a[i][j] != b[i][j]) {
                    equal= false;
                } 
            }
        }

    } else {
        equal= false;
    }
    return equal;


}

} }

Your code doesn't need ia , ib , ja , and jb . 您的代码不需要iaibjajb Since you've been told that both arrays have the same dimensions (m × n), you can simply get those two values using int m = a.length; int n = a[0].length; 既然已经知道两个数组的维数相同(m×n),则可以使用int m = a.length; int n = a[0].length;来简单地获得这两个值int m = a.length; int n = a[0].length; int m = a.length; int n = a[0].length;

That then simplifies your code to: 然后将您的代码简化为:

static boolean isEqual(int[][] a, int[][] b) {
    int m = a.length;
    int n = a[0].length;
    for (int i = 0; i < m; i++)
        for (int j = 0; j < n; j++)
            if (a[i][j] != b[i][j])
                return false;
    return true;
}

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