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如何在QCommandLineParser中使用文件名通配符

[英]How to use filename wildcards with QCommandLineParser

Is there a problem with QCommandLineParser and filename wildcards in Windows? Windows中的QCommandLineParser和文件名通配符是否存在问题?

I'm using Qt 5.8.0 opensource on Windows to build a console application. 我正在Windows上使用Qt 5.8.0开源构建控制台应用程序。 I'm trying to build a command line utility that accepts filename wildcards. 我正在尝试构建一个接受文件名通配符的命令行实用程序。 This doesn't seem to work, as it bails on the process() method. 这似乎不起作用,因为它基于process()方法。

main.cpp : main.cpp

#include <QCoreApplication>
#include <QCommandLineParser>
#include <iostream>
#include <cstdlib>

using namespace std;

int main(int argc, char** argv)
{
   QCoreApplication app(argc, argv);
   QCommandLineParser parser;
   parser.addPositionalArgument("files", "input files", "[file]...");
   parser.process(app);
   QStringList posargs = parser.positionalArguments();
   foreach(QString s, posargs)
      cout << s.toStdString() << endl;
   return EXIT_SUCCESS;
}

myapp.pro myapp.pro

CONFIG += c++14 console release
QT -= gui
sources = main.cpp

When I use the command: 当我使用命令时:

myapp somefile.txt

I get somefile.txt 我得到了somefile.txt

But this does not work with the command: 但这不适用于以下命令:

myapp *.txt

What's the best way around this? 最好的办法是什么?

QCommandLineParser just stores and retrieves the command-line arguments. QCommandLineParser只是存储和检索命令行参数。 It knows nothing about filesystem; 它对文件系统一无所知。 if you want to expand a wildcard, you'll need to take a QDir and set its name filter yourself, like this: 如果要扩展通配符,则需要使用QDirQDir设置其名称过滤器,如下所示:

#include <QCoreApplication>
#include <QCommandLineParser>
#include <QDir>

#include <iostream>

int main(int argc, char** argv)
{
   QCoreApplication app(argc, argv);
   QCommandLineParser parser;
   parser.addPositionalArgument("files", "input files", "[file]...");
   parser.process(app);
   QStringList posargs = parser.positionalArguments();
   for (auto const& s: posargs) {
       auto d = QDir{};
       d.setNameFilters({s});
       for (const auto& name: d.entryList()) {
           std::cout << name.toStdString() << '\n';
       }
   }
}

You'll need to be a bit cleverer to accept arbitrary path wildcards, of course - here, we assume there's no path separator within the argument. 当然,您需要更聪明地接受任意路径通配符-在这里,我们假设参数中没有路径分隔符。

Until this gets fixed, my solution is to make sure to enclose parameters with wildcards in them with single quotes. 在解决此问题之前,我的解决方案是确保参数中的通配符用单引号引起来。 Then parse out the wildcard in a manner similar to what Toby Speight suggested: 然后以类似于Toby Speight建议的方式解析通配符:

int main(int argc, char** argv)
{
   QCoreApplication app(argc, argv);
   QCommandLineParser parser;
   parser.addPositionalArgument("files", "input files", "[file]...");
   parser.process(app);
   QStringList posargs = parser.positionalArguments();
   for(auto s: posargs)
   {
      if(s.startsWith("'") && s.endsWith("'"))
         s = s.mid(1,s.length()-2);
      QFileInfo fi(s);
      QDirIterator iter(fi.path(), QStringList() << fi.fileName(), QDir::Files);
      while(iter.hasNext())
      {
         QString filename = iter.next();
         cout << s.toStdString() << endl;
      }
   }
   return EXIT_SUCCESS;
}

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