在Node.JS中打开多个进程

Question

There was a question, I have the code on Node.JS and I want to open several similar files at the same time (by loop), when I try to do this via execFile / spawn, the script runs, but nothing happens. When you open a loop, a single file through execFile / spawn, everything happens fine, when opening several files through a double-click in the explorer, it is also normal.

I attach the code:

 const spawn = require('child_process').spawn; const fs = require('fs'); var files = fs.readdirSync('D:\\\\Downloads\\\\runBots\\\\'); var countFiles = 0; var BotsProcess = new Array(10); var startApplication = function(){ for (var i in files) countFiles++; console.log("Bots in directory: " + countFiles); for(var j in countFiles) { BotsProcess[i] = spawn('D:\\\\Downloads\\\\runBots\\\\' + files[j], {shell : true}); } } startApplication(); 

Answer 1

The problem is the for loop. The variable countFiles is a number, not an iterable. You probably want

for (var j in files) {
    ...
}

Also, I cannot help but point out:

To get countFiles, you can simply use files.length.

You could also use a for of loop instead which will assign the value to j instead of the index, like this:

for(var j of files) {
    BotsProcess[i] = spawn('D:\\Downloads\\runBots\\' + j, {shell : true});
}