[英]Get Method JSON Response(String) Coding Complaint for key
My ResponseString is as follows, 我的ResponseString如下,
SUCCESS:
{"code":200,"shop_detail":{"name":"dad","address":"556666"},
"shop_types : [{"name":"IT\/SOFTWARE","merchant_type":"office"}]}
My Get request code with headers is as follows, 我的带有标题的Get请求代码如下,
func getProfileAPI() {
let headers: HTTPHeaders = [
"Authorisation": AuthService.instance.tokenId ?? "",
"Content-Type": "application/json",
"Accept": "application/json"
]
print(headers)
let scriptUrl = "http://haitch.igenuz.com/api/merchant/profile"
if let url = URL(string: scriptUrl) {
var urlRequest = URLRequest(url: url)
urlRequest.httpMethod = HTTPMethod.get.rawValue
urlRequest.addValue(AuthService.instance.tokenId ?? "", forHTTPHeaderField: "Authorization")
urlRequest.addValue("application/json", forHTTPHeaderField: "Content-Type")
urlRequest.addValue("application/json", forHTTPHeaderField: "Accept")
Alamofire.request(urlRequest)
.responseString { response in
debugPrint(response)
print(response)
if let result = response.result.value // getting the json value from the server
{
print(result)
let jsonData1 = result as NSString
print(jsonData1)
let name = jsonData1.object(forKey: "code") as! [AnyHashable: Any]
print(name)
// var data = jsonData1!["shop_detail"]?["name"] as? String
} }
}
When I tried to get the value for "name" its getting'[<__NSCFString 0x7b40f400> valueForUndefinedKey:]: this class is not key value coding-compliant for the key code. 当我尝试获取“名称”的值时,其含义为“ [<__ NSCFString 0x7b40f400> valueForUndefinedKey:]:此类不符合键值编码的键值。 Please guide me to get the values of name, address..?????
请指导我获取名称,地址的值。
You can use the Response Handler instead of Response String Handler : 您可以使用Response Handler代替Response String Handler :
Response Handler
响应处理程序
The response handler does NOT evaluate any of the response data.
响应处理程序不评估任何响应数据。 It merely forwards on all information directly from the URL session delegate.
它仅直接转发来自URL会话委托的所有信息。 It is the Alamofire equivalent of using cURL to execute a Request.
这与使用cURL执行请求的Alamofire等效。
struct Root: Codable {
let code: Int
let shopDetail: ShopDetail
let shopTypes: [ShopType]
}
struct ShopDetail: Codable {
let name, address: String
}
struct ShopType: Codable {
let name, merchantType: String
}
Also you can omit the coding keys from your struct declaration if you set your decoder keyDecodingStrategy
(check this ) to .convertFromSnakeCase
as already mentioned in comments by @vadian: 您也可以从你的结构声明,如果你设置你的解码器省略编码键
keyDecodingStrategy
(检查此 ),以.convertFromSnakeCase
如已通过@vadian评论中提到:
Alamofire.request(urlRequest).response { response in
guard
let data = response.data,
let json = String(data: data, encoding: .utf8)
else { return }
print("json:", json)
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
let root = try decoder.decode(Root.self, from: data)
print(root.shopDetail.name)
print(root.shopDetail.address)
for shop in root.shopTypes {
print(shop.name)
print(shop.merchantType)
}
} catch {
print(error)
}
}
For more information about encoding and decoding custom types you can read this post . 有关编码和解码自定义类型的更多信息,请阅读这篇文章 。
You can try to convert the json string to data then decode it 您可以尝试将json字符串转换为数据,然后对其进行解码
struct Root: Codable {
let code: Int
let shopDetail: ShopDetail
let shopTypes: [ShopType]
}
struct ShopDetail: Codable {
let name, address: String
}
struct ShopType: Codable {
let name, merchantType: String
}
Then 然后
let jsonStr = result as! String
let dec = JSONDecoder()
dec.keyDecodingStrategy = .convertFromSnakeCase
let res = try? dec.decode(Root.self,from:jsonStr.data(using:.utf8)!)
Note your str json may be invalid as you miss " after shop_types
so make sure it looks like this 请注意,由于您在
shop_types
之后错过了“” ,因此您的str json可能无效,因此请确保它看起来像这样
{"code":200,"shop_detail":{"name":"dad","address":"556666"}, "shop_types" : [{"name":"IT/SOFTWARE","merchant_type":"office"}]}
{“代码”:200,“ shop_detail”:{“名称”:“爸爸”,“地址”:“ 556666”},“ shop_types”:[{“名称”:“ IT /软件”,“商家类型”:“办公室”}]}
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