[英]How to make dynamic table on php codeigniter
i'm new on using codeigniter, i want to ask how to make dynamic table so when i select data from anytable form database it can be fit with the table, even the field is different. 我是使用Codeigniter的新手,我想问一下如何制作动态表,因此当我从anytable表单数据库中选择数据时,它可以适合表,即使字段不同。
so, in normally i show table like this : 因此,通常我显示这样的表:
<table class="table table-striped">
<thead>
<tr>
<th scope="col">#Number</th>
<th scope="col">Field</th>
</tr>
</thead>
<tbody>
<?php
$no = 1;
foreach ($data as $row) {?>
<tr>
<th scope="row"><?php echo $no++?></th>
<td><?php echo $row->COLUMN_NAME ?></td>
</tr>
<?php } ?>
</tbody>
</table>
but the problem when i using 3 field or more field it can't be fit, so any suggestion for it? 但是,当我使用3字段或更多字段时,问题就无法解决,因此对此有何建议?
Your problem: 你的问题:
You are fetching data from database. 您正在从数据库中获取数据。
And want to display it in table but, not sure how many columns are there. 并想在表中显示它,但不确定有多少列。
Solution: 解:
Say, you have a multi-dimensional array with n records. 假设您有一个包含n条记录的多维数组。
First get the first element (which is a database row, a table row) 首先获取第一个元素(这是数据库行,表行)
Get count of it. 得到它。
Now loop over the array. 现在循环遍历数组。
Use foreach() language construct. 使用foreach()语言构造。
It will take care of every thing. 它将处理所有事情。
Note: This solution assumes that the individual array (database records) are having same number of columns. 注意:此解决方案假定各个数组(数据库记录)的列数相同。
<?php
if (! empty($arr)) {
foreach ($arr as $elem) {
?>
<tr>
<?php
if (! emtpy($elem)) {
foreach($elem as $td) {
?>
<td><?php echo $td;?></td>
<?
}
}
</tr>
<?
}
}
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