如何在Flask的url_for方法中使用kwargs

Question

I have a certain method methodA that I need to add optional arguments to in Flask. This is typically trivial with the use of **kwargs --

@subapp.route('endpoint',methods=['GET','POST'])
def methodA(required_arg,**kwargs):
    #stuff

But my problem arises when I try and invoke **kwargs using url_for() in the template. In django , something like this would work just fine --

<a href = "{{url_for('subapp.methodA',required_arg='arg',kwargs={'additional_arg':'arg'})}}">A Link</a>

When I try that in Flask, it simply interprets the kwargs={'additional_arg':'arg'} as raw text and escapes everything, ignoring the variable in the process. This same exact question was asked earlier . However, omitting the kwargs= part as the OP did, something like

<a href = "{{url_for('subapp.methodA',required_arg='arg', {'additional_arg':'arg'})}}">A Link</a>

gives me a TemplateSyntaxError , specifically

TemplateSyntaxError: invalid syntax for function call expression

Additionally, the older question's accepted answer doesn't explain how to properly add the additional arguments in url_for . Consequently, request.args fails to capture the arguments in kwargs . Even if kwargs= remains in url_for , request.args still fails to extract the extra arguments. (To be precise, Flask doesn't even make it to the method -- it escapes kwargs entirely and yields a 404 error) The older question didn't have anything useful for my problem -- does anyone have any new advice as to what I should do?

Answer 1

以与Python中相同的方式传递额外的参数，如key='value' ：

<a href = "{{url_for('subapp.methodA', required_arg='arg', additional_arg='arg')}}">